Do patients with a family support system in place have lower pain ratings than patients with noĪ) Independent: Presence of family support systemĭ. How do physically handicapped children differ from nonhandicapped children with respect to healthĪ) Independent: Handicapped/not handicappedĬ. Does a person’s age affect psychological adjustment following burn injury?ī) Dependent: Psychological adjustment following burn injuryī. ( 1 pt) For each of the following research questions, identify the independent variable and the dependentĪ. Freezing temperature of water in degrees Kelvin. ( 1 pt) For each of the following (a through d), indicate which is a variable and which is a constant:Ī. Thanks for watching! We'll see you in the next video.1. And if your stats teacher is boring or just doesn't care to help you learn stats, go to where you can find out more about accessing our lecture videos or provide feedback on what you'd like to see. Be sure to leave your comments below to let us know how good a job we did or how we can improve. Good job!Īnd that's how we do it at Aspire Mountain Academy. Roughly is exactly what it means - roughly. That's the pattern that we see here, and so therefore, I'm going to say, “Yes, the frequencies start low, reach a maximum, then become low again, and are roughly symmetric about the maximum frequency.” Notice the word rough. Does the result appear to have a normal distribution? Why or why not? Well, looking back here in my graph in StatCrunch, I can see that the approximate pattern for a normal distribution is for the values to start low, come up to a high point in about the middle of the range, and then come back down to a low value again. So I click Continue to get the rest of the problem. And I'm just going to continue down with that same pattern to fill in the rest of the table -, 121.5 and then this one's going to be 121.7. I can do the same thing here: 121.2 minus the 0.1 gives me 121.1, or I could have just added 0.2 (the class width) into this upper limit here: 120.9 plus 0.2 gives me 121.1. In other words, I'm taking this last decimal place, and I'm just subtracting 1 from it. So that's going to be 120.9 because 120.9 gets us just to 121.0 but not exactly 121.0. So we need the next number down from 121.0 that's not 120.8, and so that number is going to be for this particular problem halfway in between. Now here we were instructed - normally when you're constructing a frequency distribution, the upper limit of one bin does not match the lower limit of the next bin. So I can just take those numbers and bring them over - 121.2, 121.4, 121.6.Īnd then the upper class limits. The class width is 0.2, so the next one is going to be 121.0, or I could just look over here at my graph here in StatCrunch and I'm listed here - these are the lower class limits for each of the bins. So guess what we get to do! Oh, we get to just transfer those numbers over! So the first one is 2, the next one is 6, the next one is 10, the next one is 5, and the next one is 2. And the best part is Value above bar gives you the values at the tops of each the bars those are the counts in each of your bins, each of your classes. And you'll see how useful that's going to be in a moment.Īll the other default values are fine for our purpose, so we're going to click Compute! Oh, ho, ho, ho, ho, ho, ho! Look at this! Oh, it’s so beautiful. The width: We're told to use a class with 0.2 volts, so I'm going to 0.2 in here.Īnd then I don't know why whoever was coding StatCrunch didn't make this the default selection because it's extremely useful, but Value above bar - I'm going to check this box next to Value above bar. Then I'm gonna put values in here in these two fields - Start at: 120.8 because we were told in the problem statement to start with 120.8 volts. Then down here under Type, I'm just gonna leave that at Frequency because we're looking for a frequency distribution we're just looking for counts, so I leave the type alone. That's the Home Volts column, so I select that column. To do that we're going to go up here in StatCrunch and go to Graph, and I'm going to select Histogram.įirst, I need to select the column where my data is located. So we're going to make a frequency distribution in graphical form and then just copy the values from that graphical form over into the tabular form for our answer fields.
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